Math, asked by jyotsna82sai, 2 months ago

What will be the area of a trapezium having two || sides as 10 cm and 12 cm and height as

4 cm​

Answers

Answered by ғɪɴɴвαłσℜ
1

\sf{\huge{\underline{\red{Given :-}}}}

  • The two || sides as 10 cm and 12 cm .

  • The height is 4 cm .

\sf{\huge{\underline{\pink{To\:Find :-}}}}

  • The area of a trapezium .

\sf{\huge{\underline{\orange{Answer :-}}}}

We have ,

\setlength{\unitlength}{1.1 cm}\begin{picture}(0,0)\linethickness{0.4mm}\qbezier(0,0)(0,0)(1.5,3)\qbezier(7,0)(7,0)(5.5,3)\qbezier(1.5,3)(1.5,3)(5.5,3)\qbezier(7,0)(7,0)(0,0)\put(1.3,3.2){$\sf A$}\put(-0.35,-0.35){$\sf B$}\put(1.5,-0.4){$\sf C$}\put(5.3,-0.4){$\sf D$}\put(5.45,3.15){$\sf F$}\put(7.2,-0.34){$\sf E$}\qbezier(5.5,0)(5.5,0)(5.5,3)\qbezier(1.5,0)(1.5,0)(1.5,3)\put(3.2, 3.2){$\sf x \: cm$}\put(2, - 0.3){\vector(1,0){3}}\put(2, - 0.3){\vector(-1,0){0}}\put(3.2,-0.7){$\sf $}\put(5.7,-0.3){\vector(1,0){1.2}}\put(5.7,-0.3){\vector(-1,0){0}}\put(6,-0.7){$\sf $}\put(0.2, - 0.3){\vector(1,0){1.2}}\put(0.2,-0.3){\vector(-1,0){0}}\put(0.55,-0.7){$\sf $}\put(0.2, - 1){\vector(1,0){6.7}}\put(0.2, - 1){\vector(-1,0){0}}\put(3,-1.45){$\sf x+2y \: cm$}\put(1.7, 1.4){$\sf $}\put(4.55,1.4){\sf }\end{picture}

The area of a trapezium = ½ × sum of || sides × height

➝ ½ × ( 10 + 12 ) × 4

➝ ½ × 22 × 4

➝ 11 × 4

44cm²

The area of a trapezium is 44cm² .

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