Question

What will be the average of first five multipliers of 6

Answer 1

Answer:

The sum of the first five multiples of 6 is the same as 6 times the first five integers:

1*6 + 2*6 + 3*6 + 4*6 + 5*6 = 6*(1+2+3+4+5)

A general formula for the sum of the first N integers is N*(N+1)/2.

So the sum of the first five multiples of 6 is equal to 6*(5*(5+1)/2) = 6*5*6/2 = 30*3 = 90.

Or you know, just list those multiples of 6 and add them together: 6+12+18+24+30 = (6+24) + (12+18) + 30 = 30+30+30 = 90

Answer 2

Answer:

18

Step-by-step explanation:

Multiples of 6:

6 × 1 = 6

6 × 2 = 12

6 × 3 = 18

6 × 4 = 24

6 × 5 = 30

To find:

Average of 6, 12, 18, 24 and 30

Solution:

Average = Sum of terms/ No. of terms

=> (6 + 12 + 18 + 24 + 30)/5

=> 90/5

=> 18

The average of first five multiples of 6 is 18

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