Question

What will be the capacity of the spherical
condutor ? whose hadius is 5cm.​

Answer 1

Answer:

When they are joined by wire, Potential of the system is V=k

r 1 +r 2

Q 1 +Q

2When wire is removed , potential of each sphere - V

1′=k

r 1

Q1′and V 2' =k

r 2

Q 2′

Just after removal wire , V=V

1' =V

2′

thus, Q

1′= r

1+r 2(Q 1 +Q 2)

r1 = 10+5(120+120)

5=80μC

Q 2' = r1 +r2 (Q 1+Q2)

r 2 = 10+5(120+120)10

=160μC

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