What will be the change in resistance of a
constantan wire when its radius is made half and
length reduced to one-fourth of its original length ?
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Answer:
R α l/r
l'=1/4l
r'=1/2r
R α (1/4l)/(1/2r)
R'= (1/4*2/1)(l/r)
R'=1/2R
Hence..the resistance will reduce by half.
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