Question

What will be the change in water temperature if 100 cal heat is applied on 1 kg of water?​

Answer 1

Heat Supplied (H) = 100 Cal = 418.4 J

Mass of water taken (m) =1kg = 1000g

Specific heat capacity of Water (c) = 4.184 J/g℃

Change in temperature (∆T) = unknown

Using the relation: H = mc∆T

=> H = mc∆T

418.4 = 1000×4.184×∆T

=> ∆T = 418.4/(1000×4.184)

= 418.4/418.4

= 1℃

Hence, change in temperature is ∆T = 1℃.