What will be the composition of the equilibrium mixture formed when 0.500
moles of propanoic acid and 0.500 moles of ethanol are reacted at 50C?
C2H5OH(l) + C2H5COOH(l) C2H5COOC2H5(l) + H2O(l)
Answers
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Answer:
C2H5OH(l) +54
Explanation:
C2H5OH(l) + C2H5COOH(l) C2H5COOC2H5(l) + H2O(l)
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