Question

What will be the compound interest on
10,000 in 2 years when rate of interest is 6%?​

Answer 1

Step-by-step explanation:

a=p(1+r/n)

a= 10000(1+6/2)

a=10000(1+3)

a=10000(4)

a=40,000

Answer 2

Step-by-step explanation:

Given That:-

Principle (P)=10,000

Time(T)=2 years

Rate of Interest (R)=6%

Amount(A)=P[1+(R/100)]^n

=>A=10000[1+(6/100)]²

=>A=10000[1+(3/50)]²

=>A=10000[(50+3)/50]²

=>A=10000[53/50]²

=>A=(10000×53×53)/(50×50)

=>A=4×53×53

=>A=11,236

Now Compound Interest=A-P

=>I=11236-10000

=>I=1,236

The compund interest is Rs. 1,236