Math, asked by mohdsajid41180, 5 months ago

what will be the compound interest on $ 25000 after 3 years at the rate of 12percent per annum​

Answers

Answered by sapana050607
6

Step-by-step explanation:

P = Rs. 25000, n = 3 years, r = 12% p.a

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r )

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 100

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 )

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×(

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112 )

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112 ) 3

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112 ) 3 =Rs.25000×

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112 ) 3 =Rs.25000× 25

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112 ) 3 =Rs.25000× 2528

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112 ) 3 =Rs.25000× 2528

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112 ) 3 =Rs.25000× 2528 ×

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112 ) 3 =Rs.25000× 2528 × 25

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112 ) 3 =Rs.25000× 2528 × 2528

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112 ) 3 =Rs.25000× 2528 × 2528

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112 ) 3 =Rs.25000× 2528 × 2528 ×

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112 ) 3 =Rs.25000× 2528 × 2528 × 25

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112 ) 3 =Rs.25000× 2528 × 2528 × 2528

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112 ) 3 =Rs.25000× 2528 × 2528 × 2528

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112 ) 3 =Rs.25000× 2528 × 2528 × 2528 =Rs.35123.20

P = Rs. 25000, n = 3 years, r = 12% p.a∴ Amount =P(1+ 100r ) n =Rs.25000×(1+ 10012 ) 3 =Rs.25000×( 100112 ) 3 =Rs.25000× 2528 × 2528 × 2528 =Rs.35123.20∴ Compound interest =Rs.(35123.20−25000)=Rs.10123.20

Answered by shreyasingh63062
1

Answer:

9000

Step-by-step explanation:

S.I = PRT/100

25000×3×12/100

9000

I hope it's well.....

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