What will be the compound interest on a sum of rs 6000 for 2 yrs at the rate of 12%
Answers
Answered by
3
Heya ✋
Let see your answer !!!
Given that
P = ₹6,000
R = 12 % p.a.
T = 2 years
Solution
When the interest is compounded annually
C.I. = P{(1+R/100)^n - 1}
= 6,000{(1+12/100)^2 - 1}
= 6,000{(100+12/100)^2 - 1}
= 6,000{(112/100)^2 - 1}
= 6,000{(28/25)^2 - 1}
= 6,000{784/625 - 1}
= 6,000{784 - 625/625}
= 6,000 × 159/625
= ₹1,526.40
Thanks :))))
Let see your answer !!!
Given that
P = ₹6,000
R = 12 % p.a.
T = 2 years
Solution
When the interest is compounded annually
C.I. = P{(1+R/100)^n - 1}
= 6,000{(1+12/100)^2 - 1}
= 6,000{(100+12/100)^2 - 1}
= 6,000{(112/100)^2 - 1}
= 6,000{(28/25)^2 - 1}
= 6,000{784/625 - 1}
= 6,000{784 - 625/625}
= 6,000 × 159/625
= ₹1,526.40
Thanks :))))
Answered by
4
Hi ,
Amount ( A ) = Rs 6000
rate of interest ( r ) = 12%
Time ( t ) = 2 years
number of times interest paid ( n ) = 2
P ( 1 + r/100 )^n = A
P ( 1 + 12/100 )² = 6000
P ( 112/100 )² = 6000
P = ( 6000 × 100 × 100 )/ ( 112 × 112 )
P = Rs 4783.16
compound interest ( C.I ) = A - P
C.I = 6000 - 4783.16
= Rs 1216.84
I hope this helps you.
: )
Amount ( A ) = Rs 6000
rate of interest ( r ) = 12%
Time ( t ) = 2 years
number of times interest paid ( n ) = 2
P ( 1 + r/100 )^n = A
P ( 1 + 12/100 )² = 6000
P ( 112/100 )² = 6000
P = ( 6000 × 100 × 100 )/ ( 112 × 112 )
P = Rs 4783.16
compound interest ( C.I ) = A - P
C.I = 6000 - 4783.16
= Rs 1216.84
I hope this helps you.
: )
Anonymous:
Sir Thanks u for the help.
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