Question

What will be the consumption of electricity in the month
of june if a bulb of 100 watt burns for 8 hours and three
tubes of 40 watt burns for 6 hours daily?
(1) 15.2 kilowatt (2) 35.6 kilowatt
(3) 45.6 kilowatt (4) 56.4 kilowatt​

Answer 1

Answer:

3

Explanation:

for bulb

power = 100 w 100/1000 kw

time =. 8hrs

electricity consumed in 1 day =

power x time

= 100/1000 x 8 = 4/5.

ele ctricity consumed in 30 days

= 4/5 x 30 = 24kw

for tubes

enrgy consumed in 1day = 6/25

energy consumed by.3 tubes = 18/25 kw

energy consumed in 30 days = 108/5

total energy consumed = 108/5 + 24

= 45.6 kw

thank yoy

Answer 2

$P=31.2\ kW.hr$ is the power consumption for the month of June.

Explanation:

Given:

• power rating of the bulb, $P_b=100\ W$

• power rating of the tube-light, $P_t=40\ W$

• operating hours of bulb per day, $t_b=8\ hr$

• operating hours of tube-light per day, $t_t=6\ hr$

Since June has 30 days, hence total power consumption:

$P=30\times(P_b\times t_b+P_t\times t_t)$

$P=30\times (100\times 8+40\times 6)$

$P=31.2\ kW.hr$

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TOPIC: electric power

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