What will be the cost of covering the white portion in figure 13.21 with a silver foil if the rate is Rs.100 per m² ? (????= 3.14)
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Given :
Side of a square = 12 m
Radius of each sector = 12 m
θ = 90°
White part is divided into two parts of equal area.
Area of part 1 = Area of square ABCD - Area of sector BAPC
Area of part 1= (Side)² - (πr²θ)/360°
= (12)² - (3.14 × 12 × 12 × 90°/360°)
= 144 - (3.14 × 3 × 12)
= 144 - 3.14 × 36
= 144 - 113.04
Area of part 1 = 30.96 m²
Area of Part 1= Area of part 2 = 30.96 m²
Total Area of white part = 2× 30.96 = 61.92 m²
Cost of covering 1m² area by silver foil = ₹100
Cost of covering 61.92 m² area by silver foil = ₹(61.92 × 100) = ₹ 6192
Hence , the Cost of covering by silver foil = ₹ 6192 .
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