Question

What will be the cost of making a closed cone of tin sheet having radius of base 6 m and slant height 8 m if the rate of making is Rs.10 per sq.m ?

Answer 1

Given the radius of base = 6m.

Given slant height = l = 8m.

We have to apply Total surface area formula because the base area is including in this and it is applied to flat surfaces.

Now,

We know that total surface area = pirl + pir^2

$= \ \textgreater \ \pi r(l + r)$

= > (22/7) * 6[8 + 6]

= > 22 * 12

= > 264

The cost of making 10 m^2 = 264 * 10

                                              = 2640.


Therefore, the cost of making a closed cone of tin sheet = 2640.



Hope this helps!

Answer 2

Answer:

Rupees 2640

Step-by-step explanation:

$r = 6m \\ l = 8m \\ tsa \: = \pi \: r \: l + \pi {r}^{2} \\ = \pi \: r(l + r) \\ = \frac{22}{7} \times 6(8 + 6) \\ = \frac{22}{7} \times 6 \times 14 \\ = 22 \times 12 \\ = 264 {m}^{2} \times 10 \\ rs.2640$