Question

What will be the current drawn by an electric bulb of 40 W, when it is connected to a
source of 220V?

Answer 1

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• $\bf\:Power\:(p)=\:40\:watts$

• $\bf\:Voltage\:(v)=\:220\:volts$

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• $\bf\:Current\:(I)=?$

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we know that,

$\bf\:P=\:V\times\:I$

Now,putting the above values in this Formula

$\bf\:40=220\times\:I$

$\bf\:I=\dfrac{40}{220}$

$\bf\:I=\dfrac{2}{11}$

$\bf\:I=0.18\:ampere$

Thus, the current (I) will be 0.18 ampere.

Some important formula of electric power:-

• First formula of power (p) = V × I
• Second formula of power (p) = l² × R
• Third formula of power (p) = v²/R

Answer 2

Question :-

• What will be the current drawn by an electric bulb of 40 W when it is connect to a source of 220v ?

Answer :-

• Current ( I ) = 0.18 ampere .

Given :-

• Power = 40 watts
• Voltage = 220 volts

To find :-

• What is the current drawn by an electric bulb ?

SoLuTioN :-

As we know that

• P = V × l

where,

• P = power
• V = Voltage
• l = current

Now, putting the values in the above formula we get,

↠ 40 = 220 × l

↠ l = 40/220

↠ l = 2/11

↠ l = 0.18 ampere

Hence, the current drawn by an electric bulb is 0.18 ampere .

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↠ Extra shots :-

• The flow of electric charges is known as current electricity.
• Electric current is the rate of flow of charges per unit area per unit time. It is measured in amperes.
• Unit of charge = columbs
• Unit of electric current = columbs/sec
• In S.I system columbs/sec is known as Ampere .

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