Question

what will be the current in the circuit ​

Answer 1

Answer:

answer is

Explanation:

I hope it's a helpful for you.

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Answer 2

Answer:

2 A

Assume At point C voltage is zero . at A it will be 12 . Let at point B it's x .

Now KVL at point A

$\frac{12 - 0}{12} + \frac{x - 0}{6} = i \implies6i = x + 6$

KVL at point B

$\frac{x - 0}{6} = \frac{12 - x}{6} \\ 2x = 12 \\ x = 6$

Use first equation

$6i = x + 6 = 6 + 6 = 12 \\ i = 2 \: amp$

**Observe that 6 and 12 ohm are not in parallel

** Star Delta method is another approach to these questions