Question

What will be the current in the circuit if resistors of 30Ω, 60Ω and 20Ω are connected in parallel across a potential difference of 24 V.


24 A

2.4 A

0.24 A

None of these
Please answer this question. ​

Answer 1

Answer:

ans is 2.4A

Explanation:

1/30+1/60+1/20=1/10

so 10 is resistance.

v=IR

l=v/r

=24/10

=2.4

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Answer 2

Answer:

The current in the circuit is 2.4 A

Explanation:

Given , there are three resistors  of   30Ω, 60Ω and 20Ω ,

and the potential  difference = 24 V .

As we know that when the  resistors are connected in parallel  then total resistor is equal to

⇒$\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3}$

Therefore , the total resistance  

⇒$\frac{1}{R_T} = \frac{1}{30} +\frac{1}{60} +\frac{1}{20}$      [$R_1 = 30 , R_2 = 60 and R_3 = 20$ given]

⇒$\frac{1}{R_T} = \frac{2 +1+ 3}{60} = \frac{6}{60}$ = $\frac{1}{10}$

⇒$R_T$= 10 Ω

And the relation between Current ,Voltage and Resistance is current is equal to voltage divided by resistance ,

⇒$I = \frac{V}{R}$

Put the value of  total resistance , voltage in the above formula we get ,

$I = \frac{24}{10}$ = 2.4A   [Where 10 Ω is the total resistance  and Voltage = 24 V ]

Hence , 2.4 A the current in the circuit .

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