Question

what will be the current though an ideal capacitor. If it is connected across a 2v battery​

Answer 1

Answer:

Explanation:

An ideal capacitor of capacitance 0.2mu F is charged to a potential difference of 10V. The charging battery is then disconnected. The capacitor is then connected to an ideal inductor of self inductance 0.5mH. The current at a time when the potential difference across the capacitor is 5V, is:

Answer 3 votes

Using Energy Conservation, Initial energy stored in capacitor = Final energy stored in capacitor + Energy stored in inductor 12CVI^2 = 12CVf^2 + 12Li^2 C( Vi^2 - Vf^2) = Li^2 i = √( C(Vi^2- V_f^2)L) Here, Vi = 10 V Vf=5 V C = 0.2 mu F L = 0.5 mH On putting these values, we will get i = 0.17 A