what will be the decrease in electrostatic force if the distance between two charges is increased by 100%?
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Answer:
Let the initial distance between the charges q
1
and q
2
be r.
Thus force acting between the charges initially F=
r
2
kq
1
q
2
New distance between the charges r
′
=1.2r
Thus, new force acting between the charges F
′
=
(r
′
)
2
kq
1
q
2
∴ F
′
=
(1.2r)
2
kq
1
q
2
=
1.44r
2
kq
1
q
2
Percentage decrease in force
F
F−F
′
×100=
r
2
kq
1
q
2
r
2
kq
1
q
2
−
1.44r
2
kq
1
q
2
×100
∴
F
F−F
′
×100=
1.44
0.44
×100=31%
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