Question

what will be the decrease in electrostatic force if the distance between two charges is increased by 100%?​

Answer 1

Answer:

Let the initial distance between the charges q

1

and q

2

be r.

Thus force acting between the charges initially F=

r

2

kq

1

q

2

New distance between the charges r

′

=1.2r

Thus, new force acting between the charges F

′

=

(r

′

)

2

kq

1

q

2

∴ F

′

=

(1.2r)

2

kq

1

q

2

=

1.44r

2

kq

1

q

2

Percentage decrease in force

F

F−F

′

×100=

r

2

kq

1

q

2

r

2

kq

1

q

2

−

1.44r

2

kq

1

q

2

×100

∴

F

F−F

′

×100=

1.44

0.44

×100=31%

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