Question

what will be the. distance and displacement of a body traveling in a circular orbit whose radius is equal to 7 times of value of π after it makes two and half revolution​

Answer 1

Answer:

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Step-by-step explanation:

According to question, body moves in a circular path of radius 7 . So, during one complete revolution the distance (s) moved by the body is equal to the circumference of the circular path, i.e. 2πr.

where, r= radius of circular path

So, for two and half revolution, body covers two complete revolution,i.e. 2*2πr distance and half revolution, i.e.2πr/2= πr distance.

Total distance(s) covered by the body

= (2*2πr) + πr

= (4πr + πr)

= 5πr

= 5*3.14*7

= 109.9

Now, as We know that displacement (d) is the straight line distance between intial and final position of the body.So, after two and half revolution, total displacement (d) of the body will be 2r, i.e.

Displacement (d) = 2*7 = 14

Therefore, Distance (s) = 109.9

and, Displacement (d) = 14