Question

What will be the distance between the two parallel lines 3x + 4y + 10 = 0 and 3x + 4y -10 = 0​

Answer 1

Answer:

4 units

Step-by-step explanation:

distance between the two parallel lines is

$d = \frac{ |c1 - c2| }{ \sqrt{ {a}^{2} + {b}^{2} } }$

here a = 3, b = 4, c1 = 10 and c2 = -10

substituting the values in the formula,

$d = \frac{ |10 + 10| }{ \sqrt{ {3}^{2} + {4}^{2} } }$

$d = \frac{20}{ \sqrt{9 + 16} }$

$d = \frac{20}{ \sqrt{25} }$

$d = \frac{20}{5}$

$d = 4 \: units$