Question

what will be the distance travelled by the object between 20 to 30 sec. shown in velocity time graph
​

Answer 1

Answer:

velocity-time graph will not give distance. It shows the change of velocity with time. It is used to find acceleration.

In the graph you can see that during 20 to 30 sec velocity is 20 and remains constant.

So the distance travelled is 20×10=200m

Answer 2

The distance traveled from one point to another is given by the area under the velocity-time graph.

The distance traveled by the object between 20 to 30 sec would be provided by calculating the area under the graph.

Distance traveled between 20 to 30 sec will be the area N, the rectangle.

Area of rectangle = l ( length) * b ( breadth)

In the question

length= 20

Breadth = 10

Hence, the area = 20*10

=200

The total distance traveled by the object is 200 m between the time interval 20 to 30 sec.