Question

What will be the electric field intensity when the distance is increased three times​

Answer 1

Answer:

1/9 of the initial electric field

Explanation:

Initially, initial E = kq/r², where,

r is the distance between the charges(or charge & field).

When r is increased by 3 times of initial,

new distance = 3r.

Therefore,

E = kq/(3r)² = kq/9r²

E = (1/9) kq/r²

E = 1/9 initial E

Electric field is 1/9 of the initial field.