Question

What will be the electricity bill amount for a month of July, if 4 fans and 8 bulbs of 40W and 80W respectively for 9 hrs are used every day. Rate of electricity is Rs 3.00 per unit?

Answer 1

Answer:

$\huge{ \underline{ \large{ \rm{ \pink{Given:}}}}}$

• Number of days (in July) = 31
• Time = 9 hrs (daily)
• 4 fans with power = 40W
• 8 bulbs with power = 80W
• Cost per unit = Rs.3

$\huge{ \underline{ \large{ \rm{ \red{Find:}}}}}$

• Electricity bill for month?

$\huge{ \underline{ \rm{ \large{ \green{Solution:}}}}}$

Let's convert the power Watt to kW

$\: \: \: \: \: \: \: \: \: \: \: { \boxed{ \sf{1W = 1000kW}}}$

• ${ \sf{Fans = \frac{40}{1000} = 0.04kW }}$

• ${ \sf{Bulb = \frac{80}{1000} = 0.08kW }}$

Let's find the electricity consumed by fan:-

• The total enrgy dissipated is given as Power × Time.
• So, E = P × T

E = 0.04 × 9

E = 0.36 kWh

E = 0.36 × 4 ( For 4 fans)

E (fan) = 1.44 kWh

Let's find the electricity consumed by Bulbs:-

E = 0.08 × 9

E = 0.72 kWh

E = 0.72 × 8 (For 8 Bulbs)

E (Bulbs) = 5.76 kWh

Total energy consumed per day:-

• Total energy = energy consumed by fan + energy consumed by bulb

E (total) = 1.44 + 5.76

E = 7.2 kWh

Energy consumed per month:-

• Energy ( month) = No.of days × Energy (per day)

E = 31 × 7.2

E (month) = 223.2 kWh

☞Electricity bill per month:-

• Electricity bill for month = cost per unit × Energy consumed per month

⇒223.2 × 3

⇒ ₹669.6

${ \therefore{ \purple{ \sf{Current \: bill \: for \: month = ₹ 669.6}}}}$