Chemistry, asked by ashadabas924, 1 year ago

What will be the EMF for the cell at 298K
Zn(s) | Zn^2+(0.2M) || Fe^3+(0.001M) | Fe(s)
If E° Fe^3+ / Fe = -0.036 and E° Zn^2+ / Zn = -0.76 volt ?
Please answer quickly if you know

Answers

Answered by karunnagraj
0

E°cell=Ecathode-Eanode

Similar questions