Question

what will be the energy (kj/mol)of an electron residing in n=3 in hydrogen atom?

Answer 1

Total energy (T.E) of electron in any orbit acc. to Bohr model is given by

T.E = 13.6 × z^(2)/n^(2)

where z is atomic no. and n is principal quantum no. which represents orbit.

now for 3rd orbit or hydrogen

T.E = 13.6 × 1^(2) / 3^(2) eV

= 13.6 / 9

=1.51 eV

Now to convert eV ( electron Volt) into joule , multiply it by 1.6 × 10^(-19) i.e charge of electron.

1.51 × 1.6 × 10^(-19) ==> 2.4 × 10^(-19) J/ mole

Now for Kilo joule per mole divide the above no. by 1000 which will give.

2.4 × 10^(-22) kJ/ mole

Answer 2

Answer:

Here n = 3

Energy of the stationary state is given by =

E = -2.18*10^(-18)*1/n^2J

=-2.18*10^(-18)*1n^2*6.022*10^23*10^(-3)

KJMol

=-2.18*10^(-18)*1/3^2*6.022*10^23*10^(-3)

= -0.242*6. 022*10^23 KJ/mol

= -1.458*10^2. kJ/mol

= - 145.8 KJ/mol

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