Question

what will be the energy of each photon in monochromatic light if frequency 5×10¹⁴HZ?​

Answer 1

Answer:

dual nature of radiation and matter.

givern. V=6×10

+14

Hz

power emitted by light p=2×10

−3

w

energy of one photon is given by

energy =hv→i

Number of photons emitted per second =

enwrgy of one photon

power

=

6.63×10

−34

×6×10

14

2×10

−3

⇒ 5.03×10

15

→ ii

Explanation:

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