Question

what will be the equivalent weight of metal if the weight of metal oxide is x gram containing y gram of oxygen??

Answer 1

Metal oxide = x gm

Oxygen = y gm

Metal = (x-y) gm

8 gm of oxygen will combine with 8(x-y)/y gm of metal

Equivalent mass of metal = 8(x-y)/y gm

Answer 2

Answer: $\frac{x-y}{y}\times 8$ g.

Explanation:

Equivalent mass of a metal is defined as the mass which combines with 8 gram of oxygen or 35.5 grams of chlorine or 1 gram of hydrogen.

Given: Mass of metal oxide = x g

mass of oxygen = y g

Thus mass of metal = Mass of metal Oxide - mass of oxygen = ( x- y) g

y gram of oxygen combine with = ( x- y) g of metal

So 8 gram of oxygen combines with =$\frac{x-y}{y}\times 8$ of metal

Thus equivalent mass of metal is $\frac{x-y}{y}\times 8$ g.