What will be the final pressure of a gas when 5 L of it originally at 1 atm is forced a 400 mL container? The temperature remains constant.
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Answered by
0
Answer:
idk
Explanation:
Answered by
2
Answer:
12.5 ATM
Explanation:
this can be solved by using Boyle's law
P1V1=P2V2
1 x 5 = P2 x 0.4 (we have to convert 400 ml to liter)
5/0.4=P2
P2= 12.5 ATM
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