what will be the focal lenght of lens having power of -0.2D
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P = 1/f. (p = power, f= focal length )
-0.2 = 1/f
f = 1/-0.2
f = -5 m
plz mark it as brainlist of it helps u
-0.2 = 1/f
f = 1/-0.2
f = -5 m
plz mark it as brainlist of it helps u
amaam1234:
which type of lens is it
Answered by
4
1/-0.2 because the formula of power of lens is P(D)= 1/focal length of lens
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