Question

What will be the frequency of photon of wavelength 2225 angstrom travelling in vacuum

Answer 1

Answer:

1.03 x 10^12

Explanation:

Given,wavelength of photon=2225 A^0

we know that relation between frequency and wavelength

ω=c/λ

  =3.10^8÷2225×10^-10

  =0.00103×10^18

  =1.03×10^12

∴The frequency of photon=1.03×10^12

Answer 2

Answer:

Frequency of photo is $1.35\times10^{15} s^{-1}$

Explanation:

Frequency is the number of waves that pass a fixed point in unit time; also, the number of cycles or vibrations undergone during one unit of time by a body in periodic motion.

Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire. In wireless systems, this length is usually specified in meters (m), centimeters (cm) or millimeters (mm). In the case of infrared (IR), visible light, ultraviolet (UV), and gamma radiation (γ), the wavelength is more often specified in nanometers (nm), which are units of $10^{-9}$m, or angstroms (Å), which are units of $10^{-10}$ m.

Wavelength is inversely related to frequency, which refers to the number of wave cycles per second. The higher the frequency of the signal, the shorter the wavelength.

Wavelength, $\lambda =2225A=2225\times10^{-10}$

Speed of light, $c=3\times10^{8} m/s$

So,

$c=\nu \lambda$

$\nu=\frac{c}{ \lambda}$

$\nu=\frac{3\times10^{8} }{2225\times10^{-10} }$

$\nu=1.35\times10^{15} s^{-1}$

Hence, frequency of photo is $1.35\times10^{15} s^{-1}$

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