Question

what will be the frictional force if 10kg mass is moving on a horizontal rough surface having coefficient of friction to be 0.2

Answer 1

Explanation:

In horizontal direction, two forces are acting on the block : 100 N force and friction force (f)

f=μN=μmg=0.5×10×10=50N

So, net force acting on the block in horizontal direction = 100 N-50 N = 50 N

acceleration of the block = Net force / mass of block = 50 N/10 kg = 5 ms

−2