Question

What will be the general solution of :
tanx+tan2x+tan3x = tanx. tan2x. tan3x
1. x= nπ/3
2.x=nπ+π/3
3.x=nπ+-π/4
4.x=nπ/6

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Answer 1

tan x + tan 2x + tan 3x ( 1 - tan x tan 2x ) = 0 

tan x + tan 2x = - tan 3x ( 1 - tan x tan 2x ) 

( tan x + tan 2x )/ ( 1 - tan x tan 2x ) = - tan 3x 

tan 3x = - tan 3x 

2 tan 3x = 0 

tan 3x = 0 

3x = 2kpi where k = 0, 1,2,3,4,5,.............. 

 x = 2 k pi/3 where k = 0 , 1, 2 ,3 , 4 , 5 , 6.............

Answer 2

Answer:

YOUR ANS IS OPTION 2

Step-by-step explanation:

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