What will be the greatest number that divides 1023 and 750 leaving remainders 3 and 2, respectively?
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First number = 1023
Remainder =3
Then, new number = 1023 – 3 = 1020
Second number = 750
Remainder = 2
Then, new number = 750 – 2 = 748
The HCF of 1020 and 748
1020 = 4 x 15 x 17
748 = 4 x 11 x 17
Common factors = 4 x 17 = 68
Thus, the HCF of 1020 and 748 is 4 x 17 = 68
Hence, the answer is 68.
hope it helps
Remainder =3
Then, new number = 1023 – 3 = 1020
Second number = 750
Remainder = 2
Then, new number = 750 – 2 = 748
The HCF of 1020 and 748
1020 = 4 x 15 x 17
748 = 4 x 11 x 17
Common factors = 4 x 17 = 68
Thus, the HCF of 1020 and 748 is 4 x 17 = 68
Hence, the answer is 68.
hope it helps
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