Question

.. What will be the H.C.F. of (2^4 x 3^3 x 5^6 x 9), (2 x 3^2 x 5^3 x 9^2) and (2^3 x 3^5 x 5 x 9^7).​

Answer 1

Answer:

x  

5

+2x  

4

+x  

3

andx  

7

−x  

5

 

⇒x  

3

(x  

2

+2x+1)⇒x  

3

(x+1)(x+1)

x  

7

−x  

5

⇒=x  

5

(x  

2

−1)⇒x  

5

(x+1)(x−1)

∴Required H.C.F=x  

3

(x+1)

Answer 2

Answer:

810

Step-by-step explanation:

=(2^4 x 3^3 x 5^6 x 9)

=2x2x2x2x3x3x3x5x5x5x5x5x5x9

=(2x3^2x5^3x9^2)

=2x3x3x5x5x5x9x9

=(2^3x3^5x5x9^7)

=2x2x2x3x3x3x3x3x5x9x9x9x9x9x9x9

HCF = 2x3x3x5x9

= 18x45

= 810