Question

What will be the H+ con when 4 gm NaOH dissolved in 1000 ml. of water :

Answer 1

At first, we have to calculate the [OH] conc. because we already know that the product of conc. of [H] and [OH] is equal to 1 x 10^-14(calculated at standard states).  

From the ques., we have  

amount of solute = 4 g  

molar mass of NaOH = 40 g  

Vol. of water = 1000 ml i.e. 1 litre  

Now, applying the formula of Molarity for calculating [OH] conc. , we have  

[OH] = 4/40 x 1  

=0.1 mol/litre  

Now,  

[H][OH] = 1 x 10^-14  

[H] = 1 x 10^-14 / 0.1  

=1 x 10^-13 M