Question

what will be the heat generate in an instrument of resistance 100ohm is connected to a potential of 230v​

Answer 1

Answer:-

• Resistance=R=100ohm
• Potential difference=V=230V
• Time=t=1s
• Current=I=?
• Heat=H=?

$\boxed{\sf \dfrac{V}{I}=R}$

$\\ \qquad\quad\sf\longmapsto I=\dfrac{V}{R}$

$\\ \qquad\quad\sf\longmapsto I=\dfrac{230}{100}$

$\\ \qquad\quad\sf\longmapsto I=2.3A$

Now

$\boxed{\sf H=I^2Rt}$

$\\ \qquad\quad\sf\longmapsto H=(2.3)^2\times 100\times230$

$\\ \qquad\quad\sf\longmapsto H=529\times 100\times 230$

$\\ \qquad\quad\sf\longmapsto Heat=12167000J$

$\\ \qquad\quad\sf\longmapsto Heat=12.2\times 10^5J$

$\\ \qquad\quad\sf\longmapsto Heat=12.2\times 10^2KJ$

$\\ \qquad\quad\sf\longmapsto Heat=12.2\times 10^2units$