What will be the heat generated in the coil of resistance 50 ohm in joule when a current of 6 amphere flows through it for 2 minutes?
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Answered by
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Using the formula
H=I^2Rt
I=6A.
R=50
t=2Min =(2×60)sec=120sec
The steps are attached with this image and The Heat energy produced is 216000J.
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H=I^2Rt
I=6A.
R=50
t=2Min =(2×60)sec=120sec
The steps are attached with this image and The Heat energy produced is 216000J.
Please don't forget to mark as the brainliest
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5
Answer:
answer is 2.16 ×10^5 joules
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