Question

What will be the highest three digit number which when divided by 3, 7 and

21 leaves remainder 2?​

Answer 1

SOLUTION

TO DETERMINE

The highest three digit number which when divided by 3, 7 and 21 leaves remainder 2

EVALUATION

Here the given numbers are 3 , 7 , 21

Now the LCM of 3 , 7 , 21 = 21

Now the highest three digit number = 999

If we divide 999 by 21 we get 47 as Quotient and 12 as Remainder

So the highest three digit number which is completely divisible by 3, 7 and 21 is 987

So the highest three digit number which when divided by 3, 7 and 21 leaves remainder 2 is

$= 987 + 2$

$= 989$

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Answer 2

Step-by-step explanation:

989 ans