Question

what will be the horizontal range of projectile range of a projectile if the velocity of a projectile is increased to double, keeping constant angle of projection ?

Answer 1

Answer:

The horizontal range becomes 4 times the original range

Explanation:

Let R1 be the initial range

R1 = u^2sin2Φ/g

Now let R2 be the new range

R2 = (2u)^2 sin2Φ/g

R2 = 4u^2sin2Φ/g

R2 = 4R1