what will be the %increase in momentum of a body when both its mass and velocity are doubled
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p=mv .... If mass and volume are doubled then the new momentum is p'= 2m×2v
= 4mv
= 4(mv)
= 4p
So, the new momentum is 4 times the previous one and
%= p'/p × 100 = 400%
= 4mv
= 4(mv)
= 4p
So, the new momentum is 4 times the previous one and
%= p'/p × 100 = 400%
lakshayhasjgmailcom:
shall we not subract p from 4p as we do in profit n loss. then the %increase will be 300%
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