What will be the initial rate of a reaction if its rate constant is 10-3 min-1 and the concentration of
reactant is 0.2 mol dm-? How much of reactant will be converted into products in 200 min
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Explanation:
rate constant=10^-3 min
initial rate=ka= 10^-3*0.2=2*10^-4moldm^-3min-1
k=2.303/t loga/a-x
log a/a-x=8.68*10^-2
taking antilog
a=1.22a-1.22x
x=0.181a/a*100
=18.1%
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The specific rate constant (k) is the proportionality constant relating the rate of the reaction to the concentrations of reactants. The rate law and the specific rate constant for any chemical reaction must be determined experimentally. The value of the rate constant is temperature dependent.
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