Question

what will be the integration of the above question?​

Answer 1

Step-by-step explanation:

We have,

$\int \sqrt{1 + \sin(2x) } dx$

$= \int \sqrt{ \sin^{2} (x) + \cos^{2} (x) + 2 \sin(x) \cos(x) } dx$

$= \int (\cos(x) + \sin(x)) dx$

$= \int \cos(x) dx + \int \sin(x) dx$

$= \sin(x) - \cos(x) + c$