What will be the intensity of an electric field in which an electron experiences an electric foece equals to its weight?
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Hello!!
- Intensity of Electric Field at a point is measured by the force being experienced by a unit charge placed at that point.
- If a unit charge is taken at any location and Electric field is such that it experiences force F = 1N then, the intensity of electric field at this location is also 1unit.
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Explanation:
As per question The mass of electron is equal to the force act on an electron:
That is 9.1 ×10^-31 N.
So According to electric force formula:
E = F / q. q is charge on electron
E. = 9.1 × 10-31 / 1.67 × 10^-19.
After calculating we will get
E = 5.44 × 10^-12 N/c
Thank you
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