Question

what will be the intensity of an electric field in which an electron experiences an electric force equal to its weight ?what in case of proton?
(with steps please)

Answer 1

put weight equal to the electrostatic force on particle(proton or electron).
bot will have different weight and so u will get magnitude of electrostatic force corresponding to proton or electron.Now divide these forces by electronic charge ( +e for proton ,-e for electron) and it will result in electric field intensities corresponding to them.

Answer 2

Answer: 1.045x10^-7

Explanation:

Given, mg=kq1q2/r^2

E=kq1q2/r^2xq0

E=mg/q0

Where, m= mass of proton

g= 10

q0= charge of respective proton

Now solve it