what will be the internal curved surface area of metal cylinderical pipe whose internal diameter is 4cm and length is 21 cm
Answers
Answered by
0
Answer:
264 cm²
Step- by-step explanation :
CSA of a cylinder = 2πrh
= 2*22/7 *2*21
= 44*2*3
= 264 cm²
Answered by
2
Given,
internal diameter of the pipe = 4 cm
length of the pipe = 21 cm
To find,
The internal curved surface area of the pipe.
Solution,
We can simply solve this mathematical problem by using the following mathematical process.
Internal radius = 4/2 = 2 cm
Internal curved surface area = 2 × π × internal radius × height = 2 × 22/7 × 2 × 21 = 264 cm²
(In the same way we can also find the external curved surface area if the external diameter is given.)
Hence, the internal curved surface area of the pipe is 264 cm².
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