Accountancy, asked by demonsking52801, 11 months ago

what will be the journal entry for this question?

1)accepted a bill at one month for ₹15,000 drawn by Dinesh.

2) received a b/r from bahadur for ₹20,000 at 1 month.

3) accepted a bill at two months drawn by Ekta for the amount due to her. (due amount--> ₹15,000)


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Answers

Answered by Anonymous
14

1) Bills Receivable A/C. Dr. Rs.15,000


To Dinesh A/C. Rs.15,000


(Being Bill drawn by Dinesh accepted )


2)Bills Receivable A/C. Dr. Rs.20,000


To Bahadur A/C. Rs.20,000


(Being Bills Received from Bahadur)



3) Bills receivable A/C. Dr. Rs.15,000


To Ekta A/C. Rs.15,000


(Being Bills Receivable from Ekta)


On the maturity date :


1)If bills are honoured :


Cash A/C. Rs.xxx


To Bills Receivable A/C. Rs.xxx


(This applies for the above all 3 cases )


2)If bill is dishonored :


Drawee's. A/C. Dr. Rs.xxx


To Bills Receivable A/C. Rs.xxx


(Applies for all the above 3 cases)


demonsking52801: thanks a lot ma'am for giving answer
Anonymous: welcome :)
Anonymous: i said her to answer ,,
Anonymous: @demonsking ,, say me thanks too ,,,,,. ,xD
demonsking52801: thank you teddy
RohitSaketi: @Himanshu lol sahi insaan h tu xD praneeth ya random user kisiko bhi nahi chorega tu xD ..thats y i like u
Answered by Anonymous
23

Answer:

\sf cos(x-y)+cos(y-z) +cos(x-z)cos(x−y)+cos(y−z)+cos(x−z)

2 (cos x cos y + sin x sin y + cos y cos z + sin y sin z + cos x cos z + sin x sin z) = -3

3 + 2 (cos x cos y + cos y cos z + cos x cos z) + 2(sin x sin y + sin y sin z + sin x sin z) = 0

(sin² x + cos² y) + (sin² y + cos² z) + (sin² x + cos² z) + 2 (cos x cos y + cos y cos z + cos x cos z) + 2(sin x sin y + sin y sin z + sin x sin z) = 0

(sin² x + sin² y + sin² z) + 2(sin x sin y + sin y sin z + sin x sin z) + (cos² x + cos² y + cos² z) + 2 (cos x cos y + cos y cos z + cos x cos z) = 0

(sin x + sin y + sin z)² + (cos x + cos y + cos z)² = 0

(sin x + sin y + sin z)² = (cos x + cos y + cos z)² = 0

sin x + sin y + sin z = cos x + cos y + cos z = 0

HENCE \sum \rm cos(x) = cos(x) + cos(y) + cos(z)∑cos(x)=cos(x)+cos(y)+cos(z) = 0

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