Question

what will be the kinetic energy if the mass is doubled and velovity is half.
1/2 (m)2* v/2

Answer 1

Final kinetic energy (KE2) is

$\frac{1}{2} \times2 m \times {(\frac{v}{2 })^{2} }$

KE2 =$\frac{m{v}^{2} }{4}$

KE2/KE = 1/2/2

Ratio = 1/2