what will be the kinetic energy of a moving body of mass'm' and velocity 'v' if its speed increases twice?
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Answer:
4 times
Explanation:
Kinetic energy = 1/2 m v^2
If speed increases twice, v = 2v
Then kinetic energy = 1/2 m (2v)^2
= 1/2 m 4 v^2
This become 4 times the actual kinetic energy.
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