What will be the labour cost of digging a well of radius 3.5 m and height 10 at the rate of ₹60 per cubic metre???
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Area of the circle formed by the well is Given by πr²
where 'r' is the radius of the circle formed by the well.
Given that the radius of well = 3.5 m
⇒ Area of the circle formed by the well = (22/7) × 3.5 × 3.5
⇒ 22 × 0.5 × 3.5 = 38.5 m²
Volume of the digged well is given by : Area of well × height of the well
Given that the height of the well as 10m
Volume of the digged well = 38.5 × 10 = 385 m³
Given that the rate per one cubic meter as 60 Rs/-
The labour cost for digged well is 385 × 60 = 23100 Rs/-
Anonymous:
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Answered by
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Hi prachi. Good morning.
Here is your answer
![r = 3.5 \: m \\ \pi = \frac{22}{7} \\ h = 10 \: m \\ so \: volume \: ofthe \: well \\ = \pi {r}^{2} h \\ = \frac{22}{7} \times {3.5}^{2} \times 10 \\ \ = \frac{22}{7} \times 3.5 \times 3.5 \times 10 \\ = 22 \times 0.5 \times 3.5 \times 10 \\ = 385 {m}^{3} \\ now \: total \: cost \: =Rs (385 \times 60) \\ =Rs 23100 \\ r = 3.5 \: m \\ \pi = \frac{22}{7} \\ h = 10 \: m \\ so \: volume \: ofthe \: well \\ = \pi {r}^{2} h \\ = \frac{22}{7} \times {3.5}^{2} \times 10 \\ \ = \frac{22}{7} \times 3.5 \times 3.5 \times 10 \\ = 22 \times 0.5 \times 3.5 \times 10 \\ = 385 {m}^{3} \\ now \: total \: cost \: =Rs (385 \times 60) \\ =Rs 23100 \\](https://tex.z-dn.net/?f=r+%3D+3.5+%5C%3A+m+%5C%5C+%5Cpi+%3D+%5Cfrac%7B22%7D%7B7%7D+%5C%5C+h+%3D+10+%5C%3A+m+%5C%5C+so+%5C%3A+volume+%5C%3A+ofthe+%5C%3A+well+%5C%5C+%3D+%5Cpi+%7Br%7D%5E%7B2%7D+h+%5C%5C+%3D+%5Cfrac%7B22%7D%7B7%7D+%5Ctimes+%7B3.5%7D%5E%7B2%7D+%5Ctimes+10+%5C%5C+%5C+%3D+%5Cfrac%7B22%7D%7B7%7D+%5Ctimes+3.5+%5Ctimes+3.5+%5Ctimes+10+%5C%5C+%3D+22+%5Ctimes+0.5+%5Ctimes+3.5+%5Ctimes+10+%5C%5C+%3D+385+%7Bm%7D%5E%7B3%7D+%5C%5C+now+%5C%3A+total+%5C%3A+cost+%5C%3A+%3DRs+%28385+%5Ctimes+60%29+%5C%5C++++++++++++++++++++%3DRs+23100+%5C%5C+)
This is your answer. plz mark as brainliest. plz
Here is your answer
This is your answer. plz mark as brainliest. plz
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