Question

what will be the largest number that divides 163 and 243 leaving 3 AS remainder​

Answer 1

To find the largest number which divides 163 and 243 leaving remainder 3 in each case i.e. HCF.

Consider HCF be x.

In order to make 615 and 963 completely divisible by x, we need to deduct the remainder 3 from both the cases.

160 = 2x2x2x2x2x5

240= 2x2x2x2x3x5

⇒ x = 2x2x2x2x5=80

∴ largest number which divides 163 and 243 leaving remainder 6 in each case is 80.

Answer 2

Answer:

Step-by-step explanation:To find the largest number we should find  HCF.

To make 163  and 243  completely divisible by HCF , we need to subtract  the remainder 3 from both

  HCF of ( 163-3  , 243- 3 )

  HCF of (   160   ,   240   )

160 = 2x2x2x2x2x5

240= 2x2x2x2x3x5

         HCF = 2x2x2x2x5=80

∴The  largest number which divides 163 and 243 leaving remainder 6 in each case is 80.