What will be the least possible no of planks if 3pcs of timber 42,49,63 m long is divided into planks of the same length
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We should find the hcf of 42,49 , 63 m =7
1 plank=7
So,
Plank a=42/7=6
Plank b=49/7=7
Plank c=63/7=9
So total planks=6+7+9=22 Planks
1 plank=7
So,
Plank a=42/7=6
Plank b=49/7=7
Plank c=63/7=9
So total planks=6+7+9=22 Planks
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